The mass of Mr x is 50kg and the uncertainty in measurement is 1 kg.The mass of Mr y is 55kg and the uncertainty in measurement is 2 kg. Find the difference of their masses with correct uncertainties.

105 $\pm$ 3 kg

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 $\pm$ 1 kg

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 $\pm$ 3 kg

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
5 $\pm$ 3 kg

When you add or subtract observations the uncertainties get added.
Weight of X is 50 $\pm$ 1kg
Weight of Y is 55 $\pm$ 2kg
Difference in mass is 5kg (55-50)
Uncertainty is $\pm$ 3(1+2)
So difference in masses is 5 $\pm$ 3kg.

Suggest Corrections

Similar questions

The mass of Mr x is 50kg and the uncertainty in measurement is 1 kg.The mass of Mr y is 55kg and the uncertainty in measurement is 2 kg. Find the difference of their masses with correct uncertainties.

Q. If the uncertainties in the measurements of position and momentum are equal, then calculate the uncertainty in the measurement of velocity (in

{ms}^{- 1}

) of particle of mass

1.21 \times 10^{- 18} kg

. Given h =

6.6 \times 10^{- 34} J . s π = 3.1

Q. If the uncertainty in velocities of two particles A and B with mass

1.0 \times 10^{- 27} k g

and

1.0 \times 10^{- 31} k g

respectively is same, the ratio of uncertainty in the positions of A and B is :

Q. The mass of electron is

9.11 \times 10^{- 31}

Kg Planck constant is

6.626 \times 10^{- 34}

Js, the uncertainty involved in the measurement of velocity within a distance of

0.1 A^{\circ}

is:

Join BYJU'S Learning Program

The mass of Mr x is 50kg and the uncertainty in measurement is 1 kg.The mass of Mr y is 55kg and the uncertainty in measurement is 2 kg. Find the difference of their masses with correct uncertainties.

The correct option is C 5 ± 3 kg When you add or subtract observations the uncertainties get added. Weight of X is 50 ± 1kg Weight of Y is 55 ± 2kg Difference in mass is 5kg (55-50) Uncertainty is ± 3(1+2) So difference in masses is 5 ± 3kg.

The correct option is C
5 $\pm$ 3 kg

When you add or subtract observations the uncertainties get added.
Weight of X is 50 $\pm$ 1kg
Weight of Y is 55 $\pm$ 2kg
Difference in mass is 5kg (55-50)
Uncertainty is $\pm$ 3(1+2)
So difference in masses is 5 $\pm$ 3kg.