The mass of nitrogen in 1000 kg of urea $[C O (N H_{2})_{2}]$ is :

467 k g

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700.5 k g

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350.25 k g

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592.34 k g

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Solution

The correct option is A $467 k g$
$[C O (N H_{2})_{2}]$
molar mass = $60 g m$
$60 g m$ urea have $28 g m$ nitrogen so
$1000 k g$ urea will have $28 \times \frac{1000}{60} = 467 k g$ nitrogen

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What is the mass of nitrogen in 1000kg of urea, [ $C O (N H_{2})_{2}$ ]? ( Answer correct to the nearest Kg) [H = 1, C = 12, N = 14, O = 16]

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[C O (N H_{2})_{2}]

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