The correct option is C 8 g
Using the interconversion of mole-volume relationship,
We have, the number of moles,
n = Volume of gas (at STP)22.4
n =5.622.4=0.25 mol
2 moles of O are present in one mole of carbon dioxide
Number of moles of O present in 0.25 moles of carbon dioxide=2×0.25=0.5 mol
Mass of O atom = 0.5×16 = 8 g