The mass of oxygen contained in $1$ kg of potassium nitrate $(K {N O}_{3})$ will be-

478.5

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485.5

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470.5

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488.2

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Solution

The correct option is C $470.5$ g

Molecular mass of ${K N O}_{3} = 40 + 48 + 14 = 40 + 14 + 16 (3) = 102 g$

$102 g$ of $K N O_{3}$ gives $\to$ $48 g$ oxygen

$1000 g of {K N O}_{3} gives \to \frac{48 g}{102} \times 1000 = 470.5 g$

Hence, option $C$ is correct.

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The mass of oxygen contained in 1kg of potassium nitrate (KNO3) will be-

The correct option is C 470.5gMolecular mass of KNO3=40+48+14=40+14+16(3)=102 g102 g of KNO3 gives → 48g oxygen1000 g of KNO3 gives →48 g102×1000=470.5 gHence, option C is correct.

The mass of oxygen contained in $1$ kg of potassium nitrate $(K {N O}_{3})$ will be-

The correct option is C $470.5$ g

Molecular mass of ${K N O}_{3} = 40 + 48 + 14 = 40 + 14 + 16 (3) = 102 g$

$102 g$ of $K N O_{3}$ gives $\to$ $48 g$ oxygen

$1000 g of {K N O}_{3} gives \to \frac{48 g}{102} \times 1000 = 470.5 g$

Hence, option $C$ is correct.