One litre of Helium gas at a pressure of 76 cm - Hg and temperature 27 $^{0}$ C is heated till its pressure and volume are doubled. The final temperature attained by the gas is

Q. A constant volume gas thermometer shows pressure reading of 50 cm and 90 cm of mercury at 0

^{0} C

and 100

^{0} C

respectively. When the pressure reading is 60 cm of mercury, the temperature is:-

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The mass of oxygen gas occupy a volume of 11.2 lit at a temperature 270C and a pressure of 76 cm of mercury in kilogram is (molecular weight of oxygen =32)

The correct option is B 0.01456PV=mMRT11.2×10−3×1.01×105=m32×10−3×8.314×300m=0.01456

The mass of oxygen gas occupy a volume of 11.2 lit at a temperature 27 $^{0}$ C and a pressure of 76 cm of mercury in kilogram is (molecular weight of oxygen =32)

The correct option is B 0.01456
$P V = \frac{m}{M} R T 11.2 \times 10^{- 3} \times 1.01 \times 10^{5} = \frac{m}{32 \times 10^{- 3}} \times 8.314 \times 300 m = 0.01456$