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Stoichiometric Calculations

The mass of o...

Question

The mass of oxygen that would be required to produce enough CO which completely reduces $1.6$ kg $F e_{2} O_{3}$ is (atomic mass of $F e = 56$ amu) :

240

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480

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720

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960

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Solution

The correct option is A $480$ g
The reactions involved are as follows:
$F e_{2} O_{3} + C O \to F e + C O_{2}$
$2 C + O_{2} \to 2 C O$
Equivalents of $O_{2}$ $=$ Equivalents of $F e_{2} O_{3}$
$\frac{W}{8} = \frac{1.6 \times 10^{3} \times 6}{160}$ [Equivalent of $F e_{2} O_{3} = \frac{M w}{6}$ ]
$⟹ W = 480$
Hence, the mass of oxygen required would be $480$ g.

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