The mass of oxygen with which 13.5 g of aluminium will completely react is:

4 g

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8 g

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12 g

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16 g

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Solution

The correct option is C 12 g
$4 A l + 3 O_{2} \to 2 A l_{2} O_{3}$
$4 \times 27$ grams of aluminum reacts with $3 \times 32$ grams of oxygen.
108 grams of aluminum reacts with 96 grams of oxygen.
13.5 grams of alluminium reacts with X grams of oxygen.
$X = \frac{13.5 \times 96}{108} = 12$ grams.
Hence option C is correct.

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