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Question

The mass of the bullet is 2 kg and velocity of bullet after firing is 25 ms−1. If initial velocity of gun and bullet is zero, what is the final momentum of gun after firing?


A

25 kgms1

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B

25 kgms1

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C

50 kgms1

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D

50 kgms1

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Solution

The correct option is D

50 kgms1


Here, mass of the bullet, m1=2 kg, velocity of bullet v1=25 ms1
Let mass of the gun be m2 and velocity of the gun be v2
Given total initial momentum is zero because initial velocity of the gun and the bullet is zero.
According to law of conservation of momentum,
(m1u1)+(m2u2)=(m1v1)+(m2v2)
0=(2×25)+(m2v2)
(m2v2)=50 kgms1
Final momentum of the gun after firing is 50 kgms1


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