The mass of the moon is 1/81 of earth's mass and its radius 1/4 that of the earth. If the escape velocity from the earth's surface is 11.2 km/sec. its value from the surface of the moon will be
A
0.14kms−1
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B
0.5kms−1
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C
2.5kms−1
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D
5.0kms−1
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Solution
The correct option is C2.5kms−1 ve=√2GMeRe vm=
⎷2GMe81Re4=29ve =2/9×11.2kms−1=2.5kms−1