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Mass Energy Equivalence

The mass of t...

Question

The mass of the nucleus $_{7} N^{14}$ is $14.00000 a m u$ . Calculate the binding energy per nucleon of $_{7} N^{14}$ in MeV. Mass of proton $= 1.00759 a m u$ , mass of neutron $= 1.00898 a m u$ and $1 a m u = 931 M e V .$

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Solution

The mass defect of nucleus is $Δ m = (Z m_{p} + Z m_{n} - m a s s o f n u c l e u s)$
$Δ m = 7 [1.00759 + 1.300898] - 14 = 0.11500 a . m . u$
The energy equivalent of this mass is E=107.98MeV
Therefore the binding energy per nucleon is 7.713MeV

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