You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Physics

Gravitational Potential Energy

the mass of t...

Question

the mass of the ship is 1000kgs.It is to be launched from the earth's surface out into free space.The value of 'g' and 'R' are 10m/s^2 and 6400km respectively.The required energy for this work will be?

Open in App

Solution

this is a question of gravitation....... we know gravitational potential energy U = -GMm/R = - m(GM/R^2)R = -mgR... and at infinity U = 0 so del_U = Uf - Ui = 0 - (-mgR) = mgR = 100010(6400*10^3)

Suggest Corrections

Similar questions

Q. The mass of a spaceship is

1000 k g

. It is to be launched from the earths surface out into free space. The value of

g

and

R

(radius of earth) are

10 m / s

and

6400 k m

respectively. The required energy for this work will be :

A space-ship is put into a circular orbit close to Earth's surface. What additional velocity must be imparted to the ship so that it is able to escape the gravitational pull of Earth(approximately)? $(R = 6400 k m, g = 9.8 \frac{m}{s^{2}})$

Q. Taking the earth to be a uniform sphere of radius

6400 km

and the value of g at the surface to be

10 {ms}^{- 2}

, the energy needed to raise a satellite of mass

2000 kg

to a height of

800 km

above the earth's surface and to set it into circular orbit at that altitude wil be

Q. The value of

^{'} g^{'}

at a depth of

80 k m

will be (Radius of earth

= 6400 k m

and value of

^{'} g^{'}

on the surface of earth is

10 m / s^{2}

)

Q. The minimum energy required to launch a

m

kg satellite from earth's surface in a circular orbit at an altitude of

2 R

where

R

is the radius of earth, will be:

Join BYJU'S Learning Program

the mass of the ship is 1000kgs.It is to be launched from the earth's surface out into free space.The value of 'g' and 'R' are 10m/s^2 and 6400km respectively.The required energy for this work will be?

this is a question of gravitation....... we know gravitational potential energy U = -GMm/R = - m*(GM/R^2)*R = -mgR... and at infinity U = 0 so del_U = Uf - Ui = 0 - (-mgR) = mgR = 1000*10*(6400*10^3)

this is a question of gravitation....... we know gravitational potential energy U = -GMm/R = - m(GM/R^2)R = -mgR... and at infinity U = 0 so del_U = Uf - Ui = 0 - (-mgR) = mgR = 100010(6400*10^3)