The mass of the sphere is 3-2 - 10-14 kg and it carries a net charge equal to that of 10 electrons- If the electronic charge is -1-6 - 10-19 C and the acceleration of free fall is 10 ms -2 the field required to keep the sphere stationary is A- 5 - 10-6 VB- 5 - 10-5 yC- 2 - 105 V - mD- 2 - 10-4 V - m

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Standard XII

Physics

Introducing Epsilon

The mass of t...

Question

The mass of the sphere is $3.2 \times 10^{- 14} k g$ and it carries a net charge equal to that of 10 electrons. If the electronic charge is $- 1.6 \times 10^{- 19} C$ and the acceleration of free fall is $10 m s^{- 2}$ the field required to keep the sphere stationary is

5 \times 10^{- 6} \frac{V}{m}

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5 \times 10^{- 5} \frac{V}{m}

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2 \times 10^{5} \frac{V}{m}

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2 \times 10^{- 4} \frac{V}{m}

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Solution

The correct option is C $2 \times 10^{5} \frac{V}{m}$
Electrostatic force Gravitational force

qE = mg; q = ne

$E = \frac{3.2 \times 10^{- 14} \times 10}{10 \times 1.6 \times 10^{- 19}} = 2 \times 10^{5} V / m$

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Similar questions

The mass of the sphere is $3.2 \times 10^{- 14} k g$ and it carries a net charge equal to that of $10$ electrons. If the electronic charge is $- 1.6 \times 10^{- 19} C$ and the acceleration of free fall is $10 m s^{- 2}$ , the field required to keep the sphere stationary is :

The magnitude of the charge of a single electron or proton is $1.6 \times 10^{- 19} C$ . What is the net charge of a particle that has 20 electrons and 22 protons?

The magnitude of the charge of a single electron or a proton is $1.6 \times 10^{- 19} C$ .
What is the net charge of an object that has 20 electrons and 22 protons?

Q. The charge on a proton is +1.6 × 10⁻¹⁹ C and that on an electron is −1.6 × 10⁻¹⁹ C. Does it mean that the electron has 3.2 × 10⁻¹⁹ C less charge than the proton?

Q. An electron

(

mass

= 9.1 \times 10^{- 31}

; charge

= - 1.6 \times 10^{- 19} C)

experiences no deflection if subjected to an electric field of

3.2 \times 10^{5} V / m

and a magnetic field of

2.0 \times 10^{- 3} W b / m^{2}

. Both the fields are normal to the path of electron and to each other. Ifthe electric field is removed, then the electron will revolve in an orbit of radius :

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The mass of the sphere is 3.2×10−14 kg and it carries a net charge equal to that of 10 electrons. If the electronic charge is −1.6×10−19 C and the acceleration of free fall is 10ms−2 the field required to keep the sphere stationary is

The correct option is C 2×105VmElectrostatic force Gravitational force qE = mg; q = ne E=3.2×10−14×1010×1.6×10−19=2×105 V/m

The mass of the sphere is $3.2 \times 10^{- 14} k g$ and it carries a net charge equal to that of 10 electrons. If the electronic charge is $- 1.6 \times 10^{- 19} C$ and the acceleration of free fall is $10 m s^{- 2}$ the field required to keep the sphere stationary is

The correct option is C $2 \times 10^{5} \frac{V}{m}$
Electrostatic force Gravitational force

qE = mg; q = ne

$E = \frac{3.2 \times 10^{- 14} \times 10}{10 \times 1.6 \times 10^{- 19}} = 2 \times 10^{5} V / m$