The mass of uniform square plate is $120 g$ and its side length is $20 c m$ . About an axis perpendicular to the plane of plate and passing through its centre, the moment of inertia is :

8 \times 10^{- 3} k g m^{2}

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8 \times 10^{- 4} k g m^{2}

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4 \times 10^{- 3} k g m^{2}

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4 \times 10^{- 4} k g m^{2}

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Solution

The correct option is B $8 \times 10^{- 4} k g m^{2}$
$m = 0.12 k g$
$L = 0.2 m$
MI of a square plate is $\frac{m L^{2}}{6}$
$I = \frac{m L^{2}}{6} = \frac{(0.12) (0.2)^{2}}{6} = 8 \times 10^{- 4} k g m^{2}$
$= \frac{(0.12) (0.2)^{2}}{6}$
$= 8 \times 10^{- 4} k g m^{2}$

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The mass of uniform square plate is 120g and its side length is 20cm. About an axis perpendicular to the plane of plate and passing through its centre, the moment of inertia is :

The correct option is B 8×10−4kgm2m=0.12kgL=0.2mMI of a square plate is mL26I=mL26=(0.12)(0.2)26=8×10−4kgm2=(0.12)(0.2)26=8×10−4kgm2

The mass of uniform square plate is $120 g$ and its side length is $20 c m$ . About an axis perpendicular to the plane of plate and passing through its centre, the moment of inertia is :

The correct option is B $8 \times 10^{- 4} k g m^{2}$
$m = 0.12 k g$
$L = 0.2 m$
MI of a square plate is $\frac{m L^{2}}{6}$
$I = \frac{m L^{2}}{6} = \frac{(0.12) (0.2)^{2}}{6} = 8 \times 10^{- 4} k g m^{2}$
$= \frac{(0.12) (0.2)^{2}}{6}$
$= 8 \times 10^{- 4} k g m^{2}$