The mass percentage of nitrogen in urea NH 2 CON H 2 is -A- 85B- 47C- 18D- 28

The correct option is B 47Molecular mass of urea (NH_2CONH_2) = 2×Atomic mass of N + 4×Atomic mass of H + Atomic mass of C + Atomic mass of O= 60 Mass percenta ...

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Standard XII

Chemistry

Percentage Composition

The mass perc...

Question

The mass percentage of nitrogen in urea ( $N H_{2} C O N H_{2}$ ) is .

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Solution

The correct option is B 47
Molecular mass of urea ( $N H_{2} C O N H_{2}$ )
$= 2 \times$ Atomic mass of $N$ + $4 \times$ Atomic mass of $H$ + Atomic mass of $C$ + Atomic mass of $O = 60$

Mass percentage of nitrogen $= \frac{Mass of an element}{Mass of compound} \times 100 = 46.67 %$

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Calculate the percentage of nitrogen in Urea.

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The mass percentage of nitrogen in urea (NH2CONH2) is .

The correct option is B 47Molecular mass of urea (NH2CONH2) =2×Atomic mass of N + 4×Atomic mass of H + Atomic mass of C + Atomic mass of O=60 Mass percentage of nitrogen =Mass of an elementMass of compound×100=46.67 %

The mass percentage of nitrogen in urea ( $N H_{2} C O N H_{2}$ ) is .

The correct option is B 47
Molecular mass of urea ( $N H_{2} C O N H_{2}$ )
$= 2 \times$ Atomic mass of $N$ + $4 \times$ Atomic mass of $H$ + Atomic mass of $C$ + Atomic mass of $O = 60$

Mass percentage of nitrogen $= \frac{Mass of an element}{Mass of compound} \times 100 = 46.67 %$