Question

The masses $m_a$ and $m_b$ moving with velocities ${\overline{V}}_a$ $\mathrm{and}\overline{v_b}$ in opposite directions collide elastically and after the collision $m_a$ and $m_b$ move with velocities $\overline{v_b}$ and ${\overline{v}}_a$ respectively. Then the ratio $\frac{m_a}{m_b}$ is

• A. $\left|\frac{v_a-v_b}{v_a+v_b}\right|$
• B. $\frac{{\mu }_a+{\mu }_B}{{\mu }_{\alpha }}$
• C. $1$
• D. $4)\frac{1}{2}$

Answer 1

The correct option is C $1$

Since the bodies exchange their velocities, masses are equal so that $\frac{ma}{mb}=1$