Question

The masses of 15kg . 10 kg and 5 kg are suspended vertically as shown in the figure. If the string attached to the support breaks and the system falls freely. what will be the tension in the string between 10 kg and 5 kg masses? Take $g=10m{s}^{-2}$. It is assumed that the string remains straight during the motion

• A. 300 N
• B. 250 N
• C. 50 N
• D. zero

Answer 1

The correct option is D zero

Given $m_1=15㎏$

$m_2=10㎏$

$m_3=5㎏$

$g=10㎨$

Now, $\Rightarrow T=m(g-a)$

$\because g=a$

$\therefore T=m(g-g)=0$

Zero