The masses of two planets are in the ratio 1: 2. Their radii are in the ratio 1: 2. The acceleration due to gravity on the planets is in the ratio.

1: 2

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2: 1

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3: 5

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5: 3

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Solution

The correct option is B
2: 1

g = $\frac{G M}{R^{2}}$

So, $g_{1}$ = $\frac{G M_{1}}{{R_{1}}^{2}}$ and $g_{2}$ = $\frac{G M_{2}}{{R_{2}}^{2}}$ and it’s given that $M_{2}$ = 2 $M_{1}$ and $R_{2}$ =2 $R_{1}$ ,

After substituting these in the expression, we'll get, $\frac{g_{1}}{g_{2}}$ = 2: 1

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The masses of two planets are in the ratio 1: 2. Their radii are in the ratio 1: 2. The acceleration due to gravity on the planets is in the ratio.

The correct option is B 2: 1 g = GMR2​ So, g1 = GM1R12​ and g2 = GM2R22​​ and it’s given that M2​ = 2M1​ and R2​=2R1​, After substituting these in the expression, we'll get, g1g2​ = 2: 1

The correct option is B
2: 1

g = $\frac{G M}{R^{2}}$

So, $g_{1}$ = $\frac{G M_{1}}{{R_{1}}^{2}}$ and $g_{2}$ = $\frac{G M_{2}}{{R_{2}}^{2}}$ and it’s given that $M_{2}$ = 2 $M_{1}$ and $R_{2}$ =2 $R_{1}$ ,

After substituting these in the expression, we'll get, $\frac{g_{1}}{g_{2}}$ = 2: 1