Question

The matchbox measures $4$ cm $\times$ $2.5$ cm $\times$ $1.5$ cm.What is the volume of a packet containing $12$ such matchboxes?

• A. $88c{m}^3$
• B. $10c{m}^3$
• C. $180c{m}^3$
• D. $80c{m}^3$

Answer 1

The correct option is C $180c{m}^3$

The dimensions of match box are $4cm\times 2.5cm\times 1.5cm$

$\therefore$ length $=4cm$

breadth $=2.5cm$

height $=1.5cm$

Now,

Volume of $=$ length $\times$ breadth $\times$ height

One match box $=4cm\times 2.5cm\times 1.5cm$

$=15c{m}^3$

$\therefore$ Volume of one match box $=15c{m}^3$

$\Rightarrow$ Volume of $12$ match boxes $+12\times$ Volume of one match box

$=12\times 15c{m}^3$

$=180c{m}^3$

$\therefore$ Volume of packet containing $12$ match boxes $=180c{m}^3$