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Question

The matrix A satisfying the equation [1301]A=[110−1] is

A
[1410]
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B
[1410]
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C
[1201]
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D
none of these
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Solution

The correct option is D none of these
[1301]A=[1101]
Let P=[1301],Q=[1101]
PA=Q
A=P1Q
We have P=[1301]
|P|=1
Now adjP=CT=[1031]T
adjP=[1301]
Hence, P1=[1301]
So, A=[1301][1101]
A=[1401]

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