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Byju's Answer
Standard XII
Mathematics
Finding Inverse Using Elementary Transformations
The matrix ...
Question
The matrix
⎡
⎢
⎣
1
2
3
1
2
3
−
1
−
2
−
3
⎤
⎥
⎦
is
A
idempotent
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B
nilpotent
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C
involutory
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D
orthogonal
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Solution
The correct option is
A
nilpotent
Given
A
=
⎡
⎢
⎣
1
2
3
1
2
3
−
1
−
2
−
3
⎤
⎥
⎦
Now,
A
2
=
⎡
⎢
⎣
1
2
3
1
2
3
−
1
−
2
−
3
⎤
⎥
⎦
⎡
⎢
⎣
1
2
3
1
2
3
−
1
−
2
−
3
⎤
⎥
⎦
⇒
A
2
=
⎡
⎢
⎣
0
0
0
0
0
0
0
0
0
⎤
⎥
⎦
⇒
A
2
=
0
Hence,
A
is nilpotent
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Similar questions
Q.
The nilpotency index of matrix
⎡
⎢
⎣
1
2
3
1
2
3
−
1
−
2
−
3
⎤
⎥
⎦
is
Q.
A
=
⎡
⎢
⎣
1
2
3
1
2
3
−
1
−
2
−
3
⎤
⎥
⎦
, then A is a nilpotent matrix of index
Q.
Compute the indicated products
(i)
[
a
b
−
b
a
]
[
a
−
b
b
a
]
(ii)
⎡
⎢
⎣
1
2
3
⎤
⎥
⎦
[
2
3
4
]
(iii)
[
1
−
2
2
3
]
[
1
2
3
2
3
1
]
(iv)
⎡
⎢
⎣
2
3
4
3
4
5
4
5
6
⎤
⎥
⎦
⎡
⎢
⎣
1
0
3
−
3
2
0
5
4
5
⎤
⎥
⎦
(v)
⎡
⎢
⎣
2
3
−
1
1
2
1
⎤
⎥
⎦
[
1
0
1
−
1
2
1
]
(vi)
[
3
−
1
3
−
1
0
2
]
⎡
⎢
⎣
2
1
3
−
3
0
1
⎤
⎥
⎦
Q.
If
A
=
⎡
⎢
⎣
1
5
1
2
0
−
1
−
3
2
1
⎤
⎥
⎦
,
B
=
⎡
⎢
⎣
3
4
2
−
1
2
0
2
5
3
⎤
⎥
⎦
and
C
=
⎡
⎢
⎣
4
0
1
1
3
−
2
2
2
3
⎤
⎥
⎦
, then compute
(
A
+
B
)
and
(
B
−
C
)
.
Also, verify that
A
+
(
B
−
C
)
=
(
A
+
B
)
−
C
Q.
Find the inverse of matrix by adjoint method
A
=
⎡
⎢
⎣
1
2
3
2
3
1
3
1
2
⎤
⎥
⎦
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