Question

The max. speed of a particle in S.H.M. is found to be 62.8 cm/s . If the amplitude is 20 cm its period of oscillation is

• A. 1 sec
• B. 2 sec
• C. 3 sec
• D. 4 sec

Answer 1

The correct option is B 2 sec

$v_{max}=\omega A$

$62.8\frac{cm}{s}=\omega \times 20cm$

$\omega =\frac{62.8}{20}=\frac{31.4}{10}=3.14$

$\omega =\pi \frac{rad}{sec}$

$T=\frac{2\pi }{\omega }=2sec$