The maxima and minima of the function f(x)=2x3−15x2+36x+10 occur, respectively at
A
x=3 and x=2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x=1 and x=3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x=2 and x=3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
x=3 and x=4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Cx=2 and x=3 f(x)=2x3−15x2+36x+10 f′(x)=6x2−30x+36 =6(x2−5x+6) f′(x)=6(x−2)(x−3)
For critical points: f′(x)=0 6(x−2)(x−3)=0 x=2,3 f′′(x)=12x−30 f′′(2)=24−30<0 ⇒f(x) has local maxima at x=2 f′′(3)=12(3)−30=6>0 ⇒f(x) has local minima at x=3