Question

The maximum acceleration of a body moving in SHM is $a_0$ and maximum velocity is $v_0$. The amplitude of the oscillation is given by,

• A. $\frac{v_0^2}{a_0}$
• B. $a_0{v}_0$
• C. $\frac{a_0^2}{v_0}$
• D. $\frac{1}{a_0{v}_0}$

Answer 1

The correct option is A

$\frac{v_0^2}{a_0}$

Maximum acceleration, $a_0={\omega }^{2}A$

And maximum velocity, $v_0=A\omega \Rightarrow v_0^2=A^2{\omega }^2$
On dividing, $\frac{a_0}{v_0^2}=\frac{1}{A}orA=\frac{v_0^2}{a_0}$