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Percentage Composition

The maximum a...

Question

The maximum amount of ${B a S O}_{4}$ (in terms of moles) precipitated on mixing equal volume one liter each of ${B a C l}_{2}$ $(0.5 M)$ with $H_{2} {S O}_{4}$ $(1 M)$ will correspond to:

0.5 m o l e s

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1.0 m o l e

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1.5 m o l e s

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2.0 m o l e s

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Solution

The correct option is A $0.5 m o l e s$
$B a C l_{2} 1 + H_{2} S O_{4} 1 ⟶ B a S O_{4} 1 + 2 H C l$
$0.5 M$ $1 M$
$B a C l_{2}$ is the limiting reagent. Hence only $0.5$ moles of $B a S O_{4}$ is precipitated.

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