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Stoichiometric Calculations

The maximum a...

Question

The maximum amount of $B a S O_{4}$ that can be obtained on mixing $0.5$ mol of $B a C l_{2}$ with $1$ mol of $H_{2} S O_{4}$ is :

0.5

mol

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0.1

mol

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0.15

mol

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0.2

mol

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Solution

The correct option is C $0.5$ mol
Balanced chemical equation:
$B a C l_{2} + H_{2} S O_{4} \to B a S O_{4} + 2 H C l$
1 mol $B a C l_{2}$ gives 1 mol of $B a S O_{4}$ .
Hence, 0.5 mol of $B a C l_{2}$ will give 0.5 mol of $B a S O_{4}$ .

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If 0.5 mole of $B a C l_{2}$ is mixed with 0.2 mol of $N a_{3} P O_{4}$ , the maximum amount of $B a_{3} (P O_{4})_{3}$ that can be formed is:

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