Question

The maximum amount of $CaC{O}_3$ that can be obtained from 4 g of calcium as per the sequence of reaction is:

$Ca\to CaO\to CaC{O}_3$

• A. 20 g
• B. 40 g
• C. 10 g
• D. 80 g

Answer 1

The correct option is C 10 g

4 g of $Ca=\frac{4g}{40g/mol}=0.1$ mol.

The molar mass of $CaC{O}_3=100$ g/mol

0.1 mol of $Ca=0.1$ mol of $CaC{O}_3=0.1\times 100=10$ g

Hence, the maximum amount of $CaC{O}_3$ that can be obtained from 4 g of $Ca$ is 10 g.

Therefore, option C is correct.