Question

The maximum amplitude of the modulated wave is $16v$ and minimum amplitude is $4v$. The percentage modulation is

• A. $25$%
• B. $40$%
• C. $60$%
• D. $75$%

Answer 1

The correct option is C $60$%

$m_a=\frac{A_{max}-A_{min}}{A_{max}+A_{min}}=\frac{16-4}{16+4}=\frac{12}{20}=0.6\times 100=60$