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Sinusoidal Wave

The maximum a...

Question

The maximum and minimum amplitude of an AM wave are $90 m V$ and $30 m V$ respectively. The depth of modulation is

A

0.6

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B

0.5

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C

0.4

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D

0.3

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Solution

The correct option is D $0.5$
$m_{a} = \frac{E_{m a x} - E_{m i n}}{E_{m a x} + E_{m i n}} = \frac{90 - 30}{90 + 30} = \frac{60}{120} = \frac{6}{12} = 0.5$

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