The maximum and minimum values of the function $y = x^{3} - 3 x^{2} + 6$ are

2, 0

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6, 0

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6, 2

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4, 2

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Solution

The correct option is A $2, 0$
Given, $F u n c t i o n, y = x^{3} - 3 x^{2} + 6$

So for that, we have to find the critical value of $y$ so, differentiate $y$ respect to $x$

$y^{'} = 3 x^{2} - 6 x = 3 x (x - 2) = 0$

So, $X$ is either be $2 o r 0.$ these are the critical values.

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