You visited us 4 times! Enjoying our articles? Unlock Full Access!

f(x) Transforms to Its Inverse

The maximum a...

Question

The maximum area of a rectangle whose two vertices lie on the x-axis and two on the curve $y = 3 - | x |, - 3 \leq x \leq 3$ , is

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{9}{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{9}{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $\frac{9}{2}$
Take 2a and 3-a are the length of the sides of the rectangle

Suggest Corrections

Similar questions

x

y = 3 - | x |, \forall | x | < 3

x -

y = 3 - | x |, \forall | x | < 3

y = e^{- x^{2}}

y = 4 x

y = - 5 x + 6

A B C D

A

B

x -

C

D

y = x^{2} - 1

x -

Join BYJU'S Learning Program