Question

The maximum bowling speed (kms/hour) of 33 players at a cricket coaching centre is given below :
Find the modal bowling speed of players.

Bowling speed (kms/hr)	85 - 100	100 - 115	115 - 130	130 - 145
No. of Players	9	11	8	5

• A. Rs. $101$kms/hour
• B. Rs.$106$ kms/hour
• C. Rs.$115$ kms/hour
• D. Rs.$118$ kms/hour

Answer 1

Answer: (B)

Rs.$106$ kms/hour

highest frequency interval = $100-115$

so mode = $L+\frac{f_m-f_{m-1}}{(f_m-f_{m-1})+(f_m-f_{m+1})}\times w$

$L$= lower class boundary of the modal group

$f_m$ = frequency of the modal group

$f_{m-1}$ = frequency of the group before the modal group

$f_{m+1}$ = frequency of the group after the modal group

$w$= group width

mode= $100+\frac{11-9}{(11-9)+(11-8)}\times 15$

mode = $100+6$

mode = $106$