Question

The maximum data rate that a medium of $10$ KHz and signal to noise ratio of $30$ dB is roughly.

• A. $10$ Kbps
• B. $30$ Kbps
• C. $100$ Kbps
• D. $300$ Kbps

Answer 1

The correct option is B $30$ Kbps

$30$ Kbps is the maximum data rate that a medium of 10 KHz and signal to noise ratio of 30 dB is roughly.

Using channel capacity formula of Shannon : we get

C = W * log₂(1 + S/N)

30 dB S/N = 1000 S/N

C = 3000*log₂ (1+1000)

C = 30 Kbps

Now suppose the amplifier increased your signal to 1000 watts. Choose the reference power to be 10 W again, and divide the new power by the reference. Find the logarithm of the power ratio. log (100) = log (102) = 2 Multiply this result by 10 to find the number of decibels.