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Question

The maximum distance from the origin of coordinates to the point satisfying the equation z+1z=a is

A
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B
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C
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D
None of these
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Solution

The correct option is C
letz=r(cos θ+isin θ)Thenz+1z=az+1z2=a2r2+1r2+2cos2θ=a2.........(i)
Differntiating w.r.t.θ weget2rdrdθ2r3drdθ4sin 2θ=0Putting drdθ=0,we get θ=0,π2r is maximum for θ =π2, therefore from (i)
r2+1r22=a2r1r=ar=a+a2+42

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