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Byju's Answer
Standard XII
Chemistry
Stereoisomerism
The maximum e...
Question

The maximum ease of abstraction of a hydrogen atom by a chlorine atom is show by?

A
(CH3)3C−CH3
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B
(CH3)3CH2
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C
C6H5CH5
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D
CH2=CHCH
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Solution

The correct option is B (CH3)3CH2
solution:
all compounds are hydrocarbon so the reaction for abstraction of chlorine is callled chlorination
and here chlrone is present in radical form
so lets first check stabily of following hydrocarbons
Benzyl>allyl>3o>2o>1o>−CH3>Vinyl>phenyl
see figure
hence the correct option: B

2023804_1277603_ans_acb62b1ba492440dbb8030a05f580659.jpg

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Q. The maximum ease of abstraction of a hydrogen by a chlorine radical is shown in which of the following.
Q. Halogenation is a substitution reaction, where halogen replaces one or more hydrogens of hydrocarbon.
Chlorine free radical make 1∘,2∘,3∘ radicals with almost equal ease, whereas bromine free radicals have a clear preference for the formation of tertiary free radicals. So , bromine is less reactive, and more selective whereas chlorine is less selective and more effective.
The relative rate of abstraction of hydrogen by Br is
3∘(1600)>2∘(82)>1∘(1)
The relative rate of abstraction of hydrogen by Cl is
3∘(5)>2∘(3.8)>1∘(1)
CH3−CH3|C|CH3−CH2−CH3|CH−CH3Br2/hv−−−−→CH3−CH3|C|CH3−CH2−CH2−CH3|C|Br−CH3
2,Bromo-2,5,5 trimethyl hexane(x%)
What is the value of x(% yield of product) ?

989068_91713f68b9d24a0abf9f18afe6d35729.png
Q. Halogenation is a substitution reaction, where halogen replaces one or more hydrogens of hydrocarbon.
Chlorine free radical make 1∘,2∘,3∘ radicals with almost equal ease, whereas bromine free radicals have a clear preference for the formation of tertiary free radicals. So , bromine is less reactive, and more selective whereas chlorine is less selective and more effective.
The relative rate of abstraction of hydrogen by Br is
3∘(1600)>2∘(82)>1∘(1)
The relative rate of abstraction of hydrogen by Cl is
3∘(5)>2∘(3.8)>1∘(1)
F. What would be the product ratio x/y in the chlorination of propane if all the hydrogen were abstracted at equal rate ?
CH3−CH2−CH3Cl2−−→hvCH3−CH2−C(x)H2−Cl+CH3−C|Cl(y)H−CH3

989110_1f60af8679f04c5aa6253ebcf7ec8df7.png
Q. The order of decreasing ease of abstraction of hydrogen atoms in the following molecule:
462595_e2de5ed655b24f8ebe236bd80d0f0b06.png
Q. When haloalkane or alkyl halide with a β hydrogen is heated with alcoholic solution of KOH, elimination of a hydrogen atom from β carbon and halogen atom from α-carbon occurs as a result, alkene is formed as product. Since β hydrogen atom is involved in the elimination reaction, it is often called β elimination.

P and Q are respectively.


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