Question

The maximum efficiency of a heat engine operating between ${100}^{0}C$ and ${25}^{0}C$ is:

• A. $20.11$
• B. $22.2$
• C. $25.17$
• D. None

Answer 1

Answer: (A)

$20.11$

Given: $T_1={100}^{o}C=(100+273)K=373K$

$T_2={25}^{o}C=(25+273)K=298K$

Using the relation,

Efficiency, $\eta =(1-\frac{T_2}{T_1})100=(1-\frac{298K}{373K})\times 100=(1-0.799)\times 100$

$\eta =\left(0.2011\right)\times 100$

$\eta =20.11$