wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The Maximum Efficiency of a Full-Wave Rectifier is


A

100%

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

25.20%

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

42.2%

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

81.2%

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D

81.2%


Step 1: Given

The efficiency of the rectifier is η.

The maximum current is Im.

The DC current is Idc.

Step 2: Formula used

η=PdcPac, where Pdcis the power of DC power and Pac is the AC power.

Pac=I2rms(rf+Rl), where ,Irmsis the root mean square current, rf is the forward resistance, and Rlis the load resistance.

Pdc=I2dcRl

Idc=2Imπ

Step 3: Find Pdc and Pac

Find an expression for Pdc by substituting Idc=2Imπ in Pdc=I2dcRl.

Pdc=I2dcRl=2Imπ2Rl

Find an expression for Pacby substituting Irms=Im2 in Pac=I2rms(rf+Rl).

Pac=I2rms(rf+Rl)=Im22(rf+Rl)

Step 3: Find Efficiency

Find the efficiency by substituting the obtained expressions in the formula. For maximum efficiency the rf<<<<Rl, so rf+Rl=Rl.

η=PdcPac=2Imπ2RlIm22(rf+Rl)=2Imπ2RlIm22Rl=8π2

Find the percentage by multiplying by 100.

8π2×100%=81.2%

Hence, the answer is (D).


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Electric Generator
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon