Question

The maximum electric field at a distance of 11.2m from a point source is 1.96 v/m. The maximum magnetic field will be (in nanotesla)

• A. 6.53
• B. 9.87
• C. 2.38
• D. 7.99

Answer 1

The correct option is A 6.53

direction of electric field , magnetic field and the direction of propagation of the electromagnetic wave are all perpendicular to each other. Therefore magnetic field is along the y direction.
$\frac{E}{H}=\frac{{\mu }_{0}E}{B}=\sqrt{\frac{{\mu }_0}{{ϵ}_0}}\Rightarrow B=6.53\times {10}^{-9}T$