The maximum energy in the thermal radiation from a hot body $A$ occurs at wavelength of $100 μ m$ . For the second hot body $B$ , the maximum energy in the thermal radiation occurs at wavelength of $55 μ m$ . If the temperature of $A$ is times that of $B$ , then $n$ is

2.0

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0.5

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(\frac{1}{2})^{4}

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(2)^{4}

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Solution

The correct option is D $0.5$
According to Wein's displacement law:
$λ T = b$
$T = \frac{b}{λ}$
$\frac{T_{1}}{T_{2}} = n = \frac{λ_{2}}{λ_{1}} = \frac{55}{100}$ which is closest to 0.5
Hence option B is true.

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The maximum energy in the thermal radiation from a hot body A occurs at wavelength of 100μm. For the second hot body B, the maximum energy in the thermal radiation occurs at wavelength of 55μm. If the temperature of A is times that of B, then n is

The correct option is D 0.5According to Wein's displacement law:λT=bT=bλT1T2=n=λ2λ1=55100 which is closest to 0.5Hence option B is true.

The maximum energy in the thermal radiation from a hot body $A$ occurs at wavelength of $100 μ m$ . For the second hot body $B$ , the maximum energy in the thermal radiation occurs at wavelength of $55 μ m$ . If the temperature of $A$ is times that of $B$ , then $n$ is

The correct option is D $0.5$
According to Wein's displacement law:
$λ T = b$
$T = \frac{b}{λ}$
$\frac{T_{1}}{T_{2}} = n = \frac{λ_{2}}{λ_{1}} = \frac{55}{100}$ which is closest to 0.5
Hence option B is true.