The maximum energy Kmax of photoelectrons emitted in a photoelectric cell is measured using lights of various frequencies v. The given graph shows how Kmax varies with v. The slope of the graph is equal to
A
the charge of an electron
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B
the charge to mass ratio of an electron
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C
the work function of the emitter in the cell
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D
Planck's constant.
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Solution
The correct option is D Planck's constant. We know that, Kmax=eV0=h(v−v0)
This is a straight line with slope equal to h, i.e., the Planck's cosntant. Hence, the correct choice is (d).