Question

The maximum height attained by a projectile when thrown at an angle $0$ with the horizontal is found to be half the horizontal is found to be half the horizontal range Then is equal to:

Answer 1

Since angle made by the projection is zero with horizontal. So there is no change in height. It means height is zero too. As we know, $H=\frac{u^2{sin}^2\theta }{2g}$

and $sin0=0$