CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Heat Zones of the Earth

The maximum h...

Question

The maximum horizontal range is given by

A

2u sinθ/g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

2u cosθ/g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

u²/g

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
u²/g

u²/g

Suggest Corrections

thumbs-up

3

Similar questions

Q. The velocity at the maximum height of a projectile is

\frac{\sqrt{3}}{2}

times its initial velocity of projection

(u)

. Its range on the horizontal plane is

Q. The velocity at the maximum height of a projectile is

\frac{1}{2}

times its initial velocity of projection

(u)

. Its range on the horizontal plane is

R

be the range of a projectile on a horizontal plane and

h

its maximum height for a given angle of projection, find the maximum horizontal range with the same initial speed of projection is then

Q. The horizontal range of a projectile is maximum for a given velocity of projection when the angle of projection is :

Q. A projectile thrown with an initial speed

u

and the angle of projection

15^{o}

to the horizontal has a range

R

. If the same projectile is thrown at an angle of

45^{o}

to the horizontal with speed

2 u

, what will be its range?

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Summary

GEOGRAPHY

Watch in App

explore_more_icon

Explore more

Heat Zones of the Earth

Standard VIII Geography

Join BYJU'S Learning Program

CrossIcon