The maximum horizontal range of a projectile is $400 m$ . The maximum value of height attained by it will be:

100 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

200 m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

400 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

800 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $200 m$
$R_{m a x} = \frac{u^{2}}{g} = 400 m$ $(F o r θ = 45^{p})$
$H_{m a x} = \frac{u^{2}}{2 g} = \frac{400}{2} = 200 m$ $(F o r θ = 90^{o})$

Suggest Corrections

Similar questions

The maximum horizontal range of a projectile is 400 m. The maximum value of height attained by it will be

The maximum horizontal range of a projectile is 400 m. The maximum value of height attained by it will be

The maximum range of a gun on horizontal terrain is 16 km. If g = 10m/ $s^{2}$ . What must be the muzzle velocity of the shell

R

H

a = \frac{g}{4}

Join BYJU'S Learning Program