The maximum increase in X-ray wavelength that can occur during Compton scattering is

5.84 \times 10^{- 12} m

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6.84 \times 10^{- 3} m

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7.84 \times 10^{- 10} m

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4.84 \times 10^{- 12} m

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Solution

The correct option is A $4.84 \times 10^{- 12} m$
We know compton formula is
$Δ λ = λ_{f} - λ_{i} = \frac{h}{m_{e} C} (1 - c o s θ)$
For maximum increase $c o s θ = - 1$
so $Δ λ = \frac{h}{m_{e} C} (1 - (- 1))$
$= \frac{2 h}{m_{e} C}$
$= \frac{2 \times 6.63 \times 10^{- 34}}{9.1 \times 10^{- 31} \times 3 \times 10^{8}}$
$= 0.484 \times 10^{- 11} m$
$= 4.84 \times 10^{- 12} m$
So, the answer is option (D).

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The maximum increase in X-ray wavelength that can occur during Compton scattering is

The correct option is A 4.84×10−12mWe know compton formula isΔλ= λf−λi=hmeC(1−cosθ)For maximum increase cosθ=−1so Δλ=hmeC(1−(−1))=2hmeC=2×6.63×10−349.1×10−31×3×108=0.484×10−11m=4.84×10−12mSo, the answer is option (D).