The maximum integral value of a for which the equation asinx+cos2x=2a−7 has a solution is
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Solution
asinx+cos2x=2a−7 ⇒2sin2x−asinx+2a−8=0 ⇒sinx=a±(a−8)4 ⇒sinx=2(not possible), sinx=a−42 Now, −1≤sinx≤1 ⇒−1≤a−42≤1 ⇒2≤a≤6 So, the maximum integral value of a is 6.