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Question

The maximum integral value of a for which the equation asinx+cos2x=2a7 has a solution is

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Solution

asinx+cos2x=2a7
2sin2xasinx+2a8=0
sinx=a±(a8)4
sinx=2(not possible), sinx=a42
Now, 1sinx1
1a421
2a6
So, the maximum integral value of a is 6.

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