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Question

The maximum intensity in Young's double-slit experiment is I0. Distance between the slits is d=5λ, where λ is the wavelength of monochromatic light used in the experiment. What will be the intensity of light in front of one of the slits on a screen at a distance D=10d?

A
I02
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B
34I0
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C
I0
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D
I04
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Solution

The correct option is B I02
Data: x=d2=5λ2,β=λDd=λ10dd=10λ
Intensity in front of one slit =Iocos2(πxβ)=Iocos2(π4)=Io2

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