Question

The maximum length of a tension member with minimum radius of gyration 50 mm carrying load reversals due to loads other than wind or earthquake forces as per IS 800 is_____ m.

Answer 1

Maximum slenderness ratio

${\lambda }_{max}=\frac{L_{eff}}{r_{min}}=180$

$\frac{L_{eff}}{50}=180$ $(r_{min}=50mm)$

$L_{eff}=180\times 50$

$=9000mm=9m$