The maximum load that a wire can sustain is $W$ . If the wire is cut to half its value, the maximum load itcan sustain is

W

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{w}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{w}{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 W

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $W$
stress $= \frac{F}{A}$
$F = s t r e s s \times A$
still the value of maximum force or load remains the same as it dod'nt depend on length of wire.

Suggest Corrections

Similar questions

w

\frac{L}{2}

A cable that can support a load W is cut into two equal parts. The maximum load that can be supported by either part is

A wire of length L can support a load W. If the wire is broken in to two equal parts , then how much load can be suspended by one of those cut wires?

W

Join BYJU'S Learning Program