The correct option is A 2(2l+1)
We know that the first shell consists of only s orbital i.e. 1 subshell and can accommodate 2 electrons. The second shell consists of two orbitals namely s and p and it can accommodated 2 electrons in the s orbital and 6 electrons in the p orbital i.e. a total of 8 electrons in the second shell.
Likewise, the d subshell accommodates 10 electrons and f subshell accommodates 14 electrons.
Thus we see that the maximum electrons in any subshell is given using 2(2l+1).
For l=0 we have n=2
For l=1 we have n=6
For l=2 we have n=10
For l=3 we have n=14
(l is the azimuthal quantum number)