Question

The maximum number of electrons that can be accommodated in all the orbitals for which $l=3$ is _______.

• A. $6$
• B. $10$
• C. $14$
• D. $18$

Answer 1

Answer: (C)

$14$

The number of orbitals for $l=3is(2l+1)=(2\times 3+1)=7$.

Now, each orbit can accomodate $2$ electrons.

So, number of electrons $=2(2l+1)=2(2\times 3+1)=2\times 7=14$.