Question

The maximum number of electrons that can have principal quantum number, $n=3$ , and spin quantum number, $m_s=-1/2$, is:

• A. $7$
• B. $8$
• C. $9$
• D. $10$

Answer 1

Answer: (C)

$9$

For principal quantum number $(n=3)$
Number of orbitals $=n^2=9$
So, number of electrons with $m_s=\frac{1}{2}$ will be 9